#ICYDK: Keysight Technologies, Inc. announced that the company’s 5G Conformance Toolset is the first test solution to be approved for 5G New Radio (NR) device certification by PTCRB, a certification forum comprised of select leading cellular operators, accelerating commercial availability of 5G mobile devices across the ecosystem. https://goo.gl/aHtLYM
Bitcoin Cash services will resume
#ICYDK: As many of you know, Bitcoin Cash (BCH) experienced a hard fork as planned on 15 November. As a precaution, we halted Bitcoin Cash services within the Wallet until we felt the situation was stable. We now feel confident that it is safe for our users and will be resuming Bitcoin Cash services in the Wallet over the next few days.
Please note, when we resume Bitcoin Cash services in the Wallet, Bitcoin Cash (BCH) will represent Bitcoin Cash ABC. Because one result of the fork was the emergence of another BCH chain (Bitcoin Cash SV), we suggest that you confirm that the party you are transacting with is also using Bitcoin Cash ABC when sending or requesting BCH within your Wallet to avoid any loss of funds.
Have a specific question? Drop us a line, our Social Team is here to help. http://bit.ly/2LnS216
Some Irresistible Integrals, Computed Using Statistical Concepts
#ICYMI: Below are a few integrals that you won’t find in textbooks. Solving them is a good exercise for college students with some advanced calculus training. We provide the solution, as well as a general framework to compute many similar integrals. Maybe this material should be part of the standard math curriculum. Here, p, q, r are positive real numbers, with q larger than p.
The Gamma symbol represents the gamma function. It is possible that these results are published here for the first time. These are known as Frullani integrals, although the ones mentioned here are not covered by Frullani’s theorem, nor any recent generalization that I am aware of. Indeed, AI-based automated integration platforms such as WolframAlpha can not find the exact value (only an approximation) while they are able to compute standard Frullani integrals exactly. My approach to derive the exact values is different from the classical approaches, as it relies on the statistical concept of expectation, possibly leading to interesting areas of research.
How to compute such integrals?
These integrals are a particular case of the following main result, proved in the next section:
where g(x) / x tends to 1 as x tends to infinity, and f is a bounded function with a finite expectation. Some additional conditions may be required, for instance the fact that there is no singularity point in the above quotient, and that g(x) has a lower bound that is strictly positive. The expectation of f, also called average value, is defined as
For instance, if f(x) = sin(SQRT(x)), then the expectation exists, and it is equal to E(f) = 2 / Pi. (Prove it!)
The main result introduced at the beginning of this section, is rather intuitive but needs great care to prove it rigorously, including correctly stating the required assumptions on f and g to make it valid. Some cases might require working with non-Riemann integrals. Here we only provide the intuitive explanation.
Proof of the main result (sketch)
Here p, q and n are integers, with q greater than p. We are interested in the case where n tends to infinity. We approximate integrals using the Euler-Maclaurin summation formula. The approximations below become equalities as n tends to infinity.
We used the classic approximation of the harmonic series to make the logarithm terms appear. Note that for large values of k, g(k) is asymptotically equal to k. This was one of the requirements for the formula to be valid.
We also have:
Using the change of variable y = x / q in the first integral, and y = x / p in the second integral, we obtain:
Let us remark that:
* q / g(qy) is asymptotically equivalent to 1 / y (for large values of y)
* p / g(py) is asymptotically equivalent to 1 / y
* both integrals diverge, so the impact of small values of y eventually vanishes in each integral separately
* the difference between the two integrals converges
In view of this, we have:
This concludes the proof.
Related Problems
* Four Interesting Math Problems
* Curious Mathematical Problem
* Two Beautiful Mathematical Results – Part 2
* Two Beautiful Mathematical Results
* Number Theory: Nice Generalization of the Waring Conjecture
* Yet Another Interesting Math Problem – The Collatz Conjecture
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FCC Prepares Next mmWave Auction
#ICYMI: The U.S. Federal Communications Commission (FCC) moved to unleash another massive tranche of mmWave spectrum for mobile service, as it approved an auction of airwaves in the 37, 39 and 47 GHz bands for the second half of 2019. https://goo.gl/hYjmDP